factoring sums of cubes t^6+1

Question

questions says to factor sums of cubes and show all work

t^6+1

Answer 1

a³+b³=(a+b)(a²-ab+b²), so if a³=t⁶, then a=t² and b=1, therefore:

t⁶+1=(t²+1)(t⁴-t²+1)