If m varies inversely with square root of u and directly with v,
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m=kv/√u; k=m0√u0/v0, where m0, u0 and v0 are some initial values.

If v1=3v0 and u1=3u0, then:

m1=(m0√u0/v0)(3v0/√(3u0))=m0(3/√3)=m0√3. So m increases to √3 times its original value.

by Top Rated User (1.2m points)

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