find Limx→1[( x6 -1)÷(x3-1)]

Limx→1[( x6 -1)÷(x3-1)]
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1 Answer

(x^6 -1) / (x^3 -1)

x^6-1=(x^3 -1)*(x^3 +1)

so yu hav x^3+1

lim as x gotu 1...1+1=2
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