2log 12-3log6+2log24

Question

i can't get the right answer. the answer is 2.584

Answer 1

me assume thats log10

2*log10(12) -3*(log10(6) +2*log10(24)

=log10(12^2*24^2 / 6^3)

=log10(144*576 / 216)

=log10(384)

=2.5843312243675442

Answer 2

Question: evaluate 2log 12-3log6+2log24.

The expression is

E = 2log(12) - 3log(6) + 2log(24)

using n.log(x) = log(x^n),

E = log(12^2) + log(24^2) - log(6^3)

E = log([288^2]/6^3)

E = log(82,944/216)

E = log(384)

E = 2.5844 (taken to the base 10 - not natural logs)

Answer 3

2log12-3log6 2log24 =log12^2-log6^3 log24^2 =log144-log216 log576 =log(144*576/216) =log(82944/216) =log384 log384= 2.5843