how do you solve "2(x+3)^2-5=14x+17"

I need to know how to solve 2(x+3)^2-5=14x+17 step by step.
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1 Answer

2(x+3)^2 -14x =17+5=22

2x^2 +12x-14x+18 = 22

2x^2 -2x -4=0

x^2 -x-2=0

x=-1 or +2
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