This question was asked in my Astronomy Lab class.
in Other Math Topics by Level 1 User (140 points)

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

2 Answers

I read this as ((metre)^2*(kilogram)^-4(second)^3)/((metre)^-2(kilogram)^3).

This becomes: (metre)^4(kilogram)^-7(second)^3=m^4kg^-7s^3.

by Top Rated User (1.2m points)
m2kg - 4s3 /m - 2kg3
by

Related questions

1 answer
1 answer
1 answer
asked Mar 28, 2014 in Algebra 1 Answers by anonymous | 782 views
1 answer
asked Mar 28, 2014 in Algebra 1 Answers by anonymous | 613 views
1 answer
1 answer
1 answer
asked Mar 19, 2013 in Algebra 1 Answers by anonymous | 684 views
1 answer
1 answer
1 answer
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,279 answers
2,420 comments
732,278 users