In a right triangle ABC in which ∠B = 90°, a circle is drawn with AB as
diameter intersecting the hypotenuse AC and P. Prove that the tangent to the
circle at P bisects BC.
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1 Answer

Must be more kondishuns tu yer problem.

As me understand yer werds...yu hav a rite triangel with a vertikal & horizontal side.

Me thank yu sae yu draw semiserkel from middel av the vertikal side with radius=hite/2

So semiserkel go out horizontal from the top point, kerv arount tile hit the rite triangel at bottom

Me tried a sampel av this & its kleer the serkel hit the diagonal neer the bottom:

NOT at middel.  Me just did I-ball werk...its WAE off.
by

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