It is impossible.
Proof:
Pick any 5 numbers from the list,
So,
2x + 2y + 2z +2w + 2k = 100 (where x,y,z,w and k are odd number where 2 times these numbers are elements of the list)
=> x + y +z w+k = 50
=> (x+y) + (z+w) + k = 50
since, x and y are odd numbers so there sum is an even number. ie. x + y = m, where m is even.
similarly z+w = n, where n is even
So,
m + n + k = 50
=> m + n = p, where p is an even number, since sum of two even number is always even.
So,
p + k = 50
Since p is even and k is odd so the resulting number is always odd.
ie, p + k = g, where g is an odd number.
so, g = 50
but this is an contradiction as g is odd and 50 is even.
Therefore any combination of 5 numbers from the list can never yield 100.