You question doesn't say if the length is 9 inches less than the width or more than it.

I am assuming that the length is 9 inches less than the width.

L = W - 9

A = W*L = W^2 - 9W

New dimensions

L2 = 2*L = 2W18

W2 = W - 4

A2 = L2 * W2 = (2W - 18)(W - 4) = 2W^2 - 26W + 36

Difference in areas

A2 - A = 110

2W^2 - 26W + 36 - W^2 + 9W = 110

W^2 - 17W - 38 = 0

(W - 19)(W + 2) = 0

**Hence W = 19, L = 10**

- All categories
- Pre-Algebra Answers 12,306
- Algebra 1 Answers 25,235
- Algebra 2 Answers 10,430
- Geometry Answers 5,157
- Trigonometry Answers 2,637
- Calculus Answers 5,997
- Statistics Answers 3,016
- Word Problem Answers 10,085
- Other Math Topics 6,622

81,485 questions

85,664 answers

2,174 comments

69,139 users