how to solve 3x^-1 + yx^-3/x^-1y^2

write the answers with all exponents positive.
in Algebra 1 Answers by Level 1 User (120 points)

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1 Answer

(3x-1+yx-3)/x-1y2=3/y2+yx-3/(x-1y2)=

3/y2+x-3+1/y=3/y2+x-2/y=3/y2+1/(x2y).

Another way to solve this is to multiply the numerator and denominator by x3:

(3x-1+yx-3)/x-1y2=(3x2+y)/(x2y2). If this is split into two fractions we get the same answer as above.

by Top Rated User (1.2m points)

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