Solve for a in : 9a^3+18a^2−25a−50=0

Solve for a in : 9a^3+18a^2−25a−50=0

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1 Answer

9a^3+18a^2−25a−50=0

By inspection, one root is a = -2. So one factor is (a+2)

(a+2)(9a^2 - 25) = 0

(a+2)(3a-5)(3a+5) = 0

a= -2, a = 5/3, a = -5/3

by Level 11 User (81.5k points)

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