for any (+ve)integer 'a' show that gcd of (2a+1 & 9a+4)=1.

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muneepenee · Answer 1 · 2014-06-30T16:31:22+0000

?????????????? "+ve" ??????????

?????????? "gcd" ????????? maebee that shood be LCM ??????????

???????????? biggest kommon fakter ????????????

Safal Das Biswas · Answer 2 · 2014-07-07T08:15:57+0000

(2a+1) for any value of a The answer is odd number

(9a+4) for any value of a The answer is odd number or even number

2a+1<9a+1

If,a=0

then,(2a+1,9a+4)=1(gcd).

If,a=1,2,3,4,5,6,7,8,9

then also (2a+1,9a+4)=1(gcd)

By maintaining this agrument For any valve upto 9 from 0 the ans is 1

Since,Both number cant be divisibe by 2,3,4,5,6,7,8,9; Then only G.C.D that left can be conclude from Previous result is 1

Since,(2a+1,9a+4)=1(gcd) <hence proved> For,Real +whole numbers