(cotA-tanA)sinA=2cosA-secA

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1 Answer

Question: Prove (cotA-tanA)sinA=2cosA-secA.

lhs = (cotA-tanA)sinA

= (cosA /sinA - sinA/cosA)sinA

= cosA - sin^2A/cosA

= cosA - (1 - cos^2A)/cosA

= cosA - secA + cosA

= 2cosA - secA = rhs

by Level 11 User (81.5k points)

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