Let 2m be 15 m=15/2
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3 Answers

If you are asking for a Pythagorean triplet in which one number is 15 then ...

One of the earliest known Pythagorean triplets is (3,4,5).

Simply multiply by a constant (integer) value, and you have another Pythagorean triple.

In this case, multipy by 3, to give (9,12,15).

Or, multiply by 5 to give (15,20,25).
by Level 11 User (81.5k points)

The difference of the squares of two consecutive numbers is always odd: (x+1)^2-x^2=2x+1. If 2x+1=15^2=225, then x=112 and 113^2-112^2=15^2, so 113^2=112^2+15^2, which is a Pythagorean triplet (15,112,113).

Also (3,4,5) can be multiplied by 3 to give (9,12,15); or it can be multiplied by 5 to give (15,20,25); and (5,12,13) can be multiplied by 3 to give (15,36,39).

That's about it, I think, for integer sides.

by Top Rated User (1.2m points)
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