find the slope of the line through (6,1) and perpendicular to y=3/2x + 1/4
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3 Answers


Allow me to answer this question by giving you an example:
The slope of the line is:  m= (Ysub2 - Ysub1) / (Xsub2 - Xsub1), where m is the slope of the line and Xsub1 is not equal to Xsub2. 
Let the first ordered pair (4, 8) be called (Xsub1, Ysub1) and the second ordered pair (1, 6) be called (Xsub2, Ysub2). 
Substituting the values for the slope,we have  
m = (6-8) / (1-4) 
m = -2 / -3 
m = 2/3  Therefore the slope of the line is 2/3.
by Level 1 User (900 points)
Oops I failed to see your other question "find the slope of the line thru  (6,1) and perpendicular to y=3/2x + 1/4".  Here is my answer:

Two lines are perpendicular to each other if their slopes are negative reciprocals of each other. Since the slope of y=3/2x + 1/4 is 3/2 then the line perpendicular to this should have a -(2/3) slope.
by Level 1 User (900 points)
Write the equation of the line with x-intercept (–10, 0) and undefined slope.

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