x^3+2x^2-7x+4

factor then solve for f(x) = 0
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1 Answer

x^3+2x^2-7x+4 = 0

By observation (trying out different values for x) x = 1 is a root, therefore (x-1) is a factor.

(x-1)(x^2 + 3x - 4) = 0

(x-1)(x-1)(x+4) = 0

So, the roots are: x = 1 (twice), x = -4

 

by Level 11 User (81.5k points)

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