prove by the construction that the diagonals of the rhombus bisects each other

plzzzzz help me to do this problem .
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1 Answer

rombus=parallelogram with all 4 sides the same leng

if yu make 1 diagonal, yu make 2 identikal isosaleez triangels...

2 sides=outsides=same leng & side 3 is shared tween 2 triangels

That meen the 2 base angels R the same & hite the same

draw the other diagonal...same rules appli

but the hite av this triangel=hite av its reflekshun kuz 2 trianges R the same

But the hite av this triangel=half  av 1 side av the triangels from the other diagonal
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