The sum of three times the first number,twice the second number,and the third number is 9.The difference between the second number and half the third number is 10.Find the numbers
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1 Answer

If the numbers are a, b and c, then:

a+b+c=-2, so 3a+3b+3c=-6 (1)

3a+2b+c=9 (2)

b-c/2=10, b=10+c/2 (3)

(1)-(2)=b+2c=-15, b=-15-2c, therefore 10+c/2=-15-2c, 25=-5c/2, c=-(2/5)25=-10.

And b=10-10/2=5, and a=-2-(b+c)=-2-(5-10)=-2+5=3.

CHECK

a+b+c=3+5-10=-2 OK.

3a+2b+c=3×3+2×5-10=9 OK.

b-c/2=5-(-5)=5+5=10 OK.

SOLUTION: a=3, b=5, c=-10.

by Top Rated User (1.2m points)

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