solve for symmetry algebraically h(x)=3x^3+5

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y=3x^3 +5 is symmetrik around the origin...(0,0) . . . not quite...its offset up, so symmetrik bout (0,5) . . . bekaus av the x^3...(-x)^3=-(x^3) . . . so kerv go up on the rite side & down on the left side . . . & go up/down same number bout start point =(0,5)
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