the roots of eqn 2x^2-4x-7=0 are a and b.Find eqn whose roots are a^2,b^2

Question

solve the equation

Answer 1

2x^2 -4x -7=0 . . . quadratik equashun giv roots=3.1213203 & -1.1213203 . . . so a=3.1213203 & b=-1.1213203 . . . a^2=9.742532418 . . . b^2=1.257359215 . . . quashun: (x-9.742532418)*(x-1.257359215)

Answer 2

" Solution: Given 2x^2-4x-7=0
there for the root of the equation are
x=1+3/√2
x=1-3/√2
there for find the equation whose root are (a²,b²)=[(1+3/√2)²,(1-3/√2)²]
the quadratic equation =(x-(3√2+11/2))(x-(11/2-3√2))
the quadratic equation =>x²-11x+49/4=0"

Simplifying Square Roots

In mathematics square root having a significant importance while simplifying the numbers. The square root of a number results in a number which when multiplied with the same number gives the resultant number. To simplify a square root, one should 'group' or 'recognize' those number which have occurred twice or in other words have appeared 2 times as the factors of the number