What is the factored form of the ploynomial f(x)^3+64, using the sum of 2 cubes?

What would the final factor be?
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x^3+64....x^3 +4^3 . . . jenral form: a^3 +b^3=(a+b)(a^2 -ab +b^2) . . . become (x+4)*(x^2 -4x +16) . . .
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