through: (-3,-3), parallel to y=7/3x+3

Question

What is the equation of a line parallel to y=7/3x+3 that goes through point (-3,-3)

Answer 1

the given equation is in slope intercept form

y=mx+b

y=7/3x+3

m = Slope

b = y-intercept

so we know that the slope of your first line is 7/3 and the y intercept is 3

 

for two lines to be paralell they have to have the same slope.  We can start with that.  We know that the equation of the second line must start with

y=7/3x+?

to find another point on the second line you can use rise over run to move from (-3,-3) up 7 and to the right 3 on the graph to

(0,4)

since your x value for this point is 0 that is your y-intercept.

y=7/3x+4

Here is a graph of both lines: