suppose b is between a and c. use the segment addition postulate to solve for x.

also supposed to draw a sketch of the 3 collinear points and find the lengths of ab, bc, and ac. ab=3x+8, bc=2x-5, ac=23 ab=7y+9, bc=3y+4, ac=143 ab=2x+5, bc=2x-3, ac=3x+10
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1 Answer

AB+BC=AC, so 3x+8+2x-5=5x+3=23, 5x=20, x=4 and AB=3x+8=20; BC=2x-5=3, AC=5x+3=23 (as we were given).

AB=7y+9, BC=3y+4, so AC=143=10y+13, 10y=130, y=13; AB=7y+9=100; BC=3y+4=43, AC=10y+13=143 (given).

2x+5+2x-3=3x+10, 4x+2=3x+10, 4x-3x=10-2, x=8; AB=2x+5=21; BC=2x-3=13; AC=3x+10=34.

by Top Rated User (1.2m points)

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