such as 2x=4y

3xy+8=4y
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1 Answer

2x=4y, so x=2y.

3xy+8=4y.

Substitute for x: 3y×2y+8=4y,

6y²-4y+8=0,

3y²-2y+4=0, which has only a complex solution:

y²-2y/3+4/3=0, y²-2y/3=-4/3,

y²-2y/3+1/9=1/9-4/3=-11/3,

(y-⅓)²=-11/3. We cannot take the square root of each side because √(-11/3) is an imaginary number.

In complex numbers √(-11/3)=i√(11/3) and the solutions would be:

y=⅓+i√(11/3) and y=⅓-i√(11/3).

However, if your equations were 2x=4y and 3x+8=4y, then 3x+8=2x, x+8=0, x=-8 and -16=4y, so y=-4.

by Top Rated User (804k points)

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