((2x^2-5x-3)/(x^2-4)) / ((2x^2+7x+3)/(x^2+x-6)) please help
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These can be factorised to make things simpler.

2x²-5x+3=(x-1)(2x-3); x²-4=(x-2)(x+2); 2x²+7x+3=(2x+1)(x+3); x²+x-6=(x+3)(x-2).

Now rewrite the expression:

[(x-1)(2x-3)][(x+3)(x-2)]/([(x-2)(x+2)][(2x+1)(x+3)])=

[(x-1)(2x-3)]/([(x+2)(2x+1)])=

(2x²-5x+3)/(2x²+5x+2).

ago by Top Rated User (735k points)

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