(X+3)^2 - 9 ÷ X
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2 Answers

me assume that stuf shood be... (x+3)^2 -(9/x)... as x gotu 0, -9/x blo up downward...it gotu - infility... x+3 dont matter...same as 0, kompared tu infinity
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[(x+3)^2 - 9]/x

[x^2 + 2x + 9 - 9]/x

[x^2 + 2x]/x

x + 2

The function reduces to (x + 2) and the limit of this as x tends to zero is 2

by Level 11 User (80.8k points)

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