Question

Using the Law of Cosine solve for the unknown. Given: side c = 68.7, side a=46, side b=46 find angle A =?

Answer 1

CosA = -a^2 + b^2 + c^2 / 2bc cos(A) = -46^2 + 46^2 + 68.7^2 / 2 x 46 x 68.7 (if I typed in everything into my calculator right) cos(A) = .7467391304...... cos^-1(A) = cos^-1(.746) this is cos inverse A = 41.69130467

Answer 2

yu giv length av all 3 sides av 1 triangel, so me kan solv it NE-wae me want... leng=68.7, 46, & 46...2 sides the same, so it be ISOSALEEZ, base=68.7 & 2 sides up from base=46... triangel hite=30.5954, area=1050.9514, rim leng=160.7... top point=(0, 13.07967)... triangel is symmetrik bout vertikal line from middel av base, so me set... origin theer..... angels: 41.6913, 41.6913, 96.6174 deg...same angel on left & rite sides... inside serkel: rad=13.07967, senter: (0,13.07967... ourside serkel: rad=34.58038, senter(0,-3.985)