how do you solve 3x-5y = 15 and 6x+4y=24 using substitution method

Question

ow do you solve 3x-5y = 15 , 6x+4y=24 using substitution method

Answer 1

line 1: 3x-5y=15... line 2: 6x+4y =24, or 3x+2y=12, become y=-1.5x+6... line 1...3x -5*(-1.5x+6)=15... 3x +7.5x -30=15... 10.5x=45... x=4.285714286... y=-1.5x+6=-1.5*(4.285714286)+6 =6-6.428571429 =-0.428571429

Answer 2

form two equations. x+y=11........1 xy =28.........2 x=11-y....subsituting x in xy=28 then y(y-11)=28 y^2-11y=28 y^2-11y-28=0 sum=-11 product=28 y^2-4y-7y+28=0 y(y-4)-7(y-4)=0 (y-7)(y-4)=0 y=7 or 4. x(4)=28 x=28/4 x=7... so when y=4.x=7 and when. y=7. x=4.

Answer 3

3x-5y = 15.........1 6x+4y=24............2 frm eq 1 x=5y/3+5 6(5y/3+5)=24 10y+30=24 10y=24-30 10y=-6 y=-6/10 y=3/5 put y=-3/5 into eq2 6x+4(-3/6)=24 6x=24+2 6x=26 x= 26/6 x=13/3