3x + 2 7
----------------- + ---------------------
4x^2 - 4x -48 4x^2 - 20x + 16
I hope is the way it was written...
3x+2/ 4(x^2 - x -12) + 7/ 4(x^2 - 5x + 4)
take a multiple of 4 out of the denominators
3x +2 / 4(x+3)(x-4) + 7/ 4(x-1)(x-4)
factor and notice that there is a common x-4
get a common denominator for the terms
(3x+2)(x-1) +7(x+3) / 4 (x+3)(x-4)
3x^2 +2x -3x -2 +7x +21/4(x+3)(x-4)
3x^2 + 6x + 19/4(x+3)(x-4)