x - 2y = 2 --- (1)
3x + y = 6 --- (2)
From (1), we have: x = 2y + 2 --- (3)
Substituitng (3) into (2), we will get:
3(2y + 2) + y = 6
6y + 6 + y = 6
7y = 6 - 6
7y = 0
y = 0 / 7
y = 0
Substituting y = 0 into (3), we have:
x = 2(0) + 2
x = 0 + 2
x = 2
Hence, x = 2 and y = 0.