What is the approximate value of the median?

 

 

In this distribution, approximately 68% of the scores fall between 70 and 80. To capture 99% of the scores, what would the range be?
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1 Answer

There isn't enough given information to solve this problem.

I don't think we can answer this without knowing what kind of distribution we're talking about.  Yes, talking about 68% (1 standard deviation in a standard normal distribution) and 99% (around 3 standard deviations in a standard normal distribution) makes it sound like we're talking about some kind of normal distribution, but the problem doesn't state that.  We could have a piecewise distribution.  The problem does not state the maximum score.  With the possibility of a piecewise distribution, the remaining 32% of the scores could have been perfect scores or all 0's, so the only way to be certain of capturing 99% of the scores, the range would have to be 0 to a perfect score.  We can't calculate the median (mean) either, because we don't know how many of the remaining 32% of the scores are above or below the given 68% in the 70 to 80 range.

by Level 13 User (103k points)

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