(b^2-4b-21) / (b^2-11b+28) + 1/b-4
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1 Answer

(b^2-4b-21) / (b^2-11b+28) + 1/b-4

This is not an inequality but, as an expression, it can be simplified.

(b^2 - 4b - 21) / (b^2 - 11b + 28) + 1/(b - 4) =

(b - 7)(b + 3) / (b - 7)(b - 4) + 1/(b - 4) =

(b + 3) / (b - 4) + 1/(b - 4) =

{(b + 3) + 1} / (b – 4) =

(b + 4)/(b – 4)

 

by Level 11 User (81.5k points)

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