graphs for f(x)=x^2+4x-5, plot solutions for f(x)=0

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1 Answer

x^2 +4x -5=0

quadratik equashun giv roots=1 & -5

or (x-1)*(x+5)=0

parabola that tern up

kross x axis at x=1 & at x=-5

dy/dx=2x+4...tangent, set tu 0 & get 2x=-4, or x=-2

thats weer tangent=horizontal=lo point av kerv
by

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