find the sides of a polygon which has two interior angle of 120 degree and the others are 150 degree
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with 2 sides av 120 deg=240 deg, kant be triangel or 4-gon

tri 5-nog (pentagon)...sum av all inside angels gotta be 540 deg

triangel=180 deg, rektangel=360 (2*180), 5-gon=540 (3*180)

subtrakt 240 for 2 angels at 120 leev 300deg for 3 angels...1000 per...2 small

tri 6-gon (hexagon)...sum av angels=4*180=720, subtrakt 240 for first 2...

leev 480 for 4 sides=120 deg eech

maebee if yo go tu 10 or 12 sides yu kood make other angels=150
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