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 perimeter of the field is 1520 ft, what are the dimensions of the field?
in Pre-Algebra Answers by Level 1 User (220 points)

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1 Answer

 

Let the rectangular field width  = b = x ft

length = 7x ft

perimeter = 1520ft

2(l + b) = 1520

2(7x + x) = 1520

2 *8x =1520

x =  1520/2*8

x = 95

therefore, width =  x = 95ft

length = 7xft = 7*95  ft = 695 ft 

 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 

 

by Level 4 User (5.5k points)

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