the region bounded by the graph of y=x^(2) and y=x+2 sketch the region
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1 Answer

y1 = x^2

y2 = x + 2

The graph looks like this,

A = int [x=-1 .. 2] (y2 - y1) dx

A = int [-1 .. 2] (x + 2 - x^2) dx

A = [x^2/2 + 2x - x^3/3] [-1 .. 2]

A = {(4/2 + 4 - 8/3) - (1/2 - 2 - (-1)/3)}

A = (10/3 + 7/6) = 9/2

Bounded Area is 4 1/2 square units

by Level 11 User (81.5k points)

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