I need to know how to solve step by step f(x)=2x^2+2x+2 and then graph it.
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1 Answer

2x^2 +2x+2=2*(x^2 +x +1)

yuze quadratik equashun on that & yu find roots=komplex numbers

that meen kerv DONT =0 for NE reel x...its alwaes > 0

1 point=(0,2)

dy/dx=4x+2...tu get horizontal tangens, set =0...4x=-2, or x=-1/2

bottom av parabola at (-0.5, 3.5)
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