Solve 8 = x ∛(x+1) + 2

Solve for x
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1 Answer

8 = x ∛(x+1) + 2

6 = x ∛(x+1)

6 = x ∛x + 1        <-----------the cube root of one is still one, so even though we distribute it to both, the one                                                                     stays the same because 1 x 1 x 1 = 1.

5 = x ∛x

5/x = ∛x

125/x = x

125 = x^2

x = √125         or           x = 11.1803398875

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