An object is launched straight up into the air.  Its height in feet, or h, after t seconds is given by the equation h=-16t^2 + 48t + 10.

Determine how much time (in seconds) has elapsed from the time of launch to the time the object hits the ground.

Determine how much time has elapsed when the object is 30 feet above the ground.

Determine the maximum height reached by the projectile.

Determine the projectile's distance from the ground at the instant that the projectile is fired.
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1 Answer

-16x^2 +48x +10=0

or 16x^2 -48x -10=0

or 8x^2 -24x -5=0

x=3.1955825 or -0.1955825

tri the positiv
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