how to find the range value of x for which

Question

2x²  equally smaller than 1+x  how to find this?

Answer 1

???????? yu tri tu sae 2x^2 <= (x+1) ??????????

first tri :2x^2 -x-1=0

quadratik equashun giv (x-1)(x+0.5)=0

This meen 2x^2 <=(x+1) for x tween -0. & +1

zampel: at x=0, 2x^2=0 wich is < 1