how do I solve x2 -6x +6 = 0

Question

From what I read I should be able to find a number that multiples to 6 and adds to 6 but that's not possible.  x2 -6x +6 = 0  (that 2 means squared).  What am I missing?

Answer 1

x2- 6x  +6 =0 compare with ax2 + bx + c = 0

here a = 1; b = -6 ; c = 6;

D = b2 -4ac

   = (-6)(-6) - 4 * 1 * 6

  = 36 - 24

 = 12 [ It is not a perfect square, so, you cannot get roots what u imagined]

Use below method;

x = -b+ square root of D/2a  or -b - square root of D/2a

​x = - (-6) + square root of 12/ 2*1 or - ( -6) - square root of 12/2*1

x = 6 + 2*square root of 3/2 or 6 - 2* square root of 3/2

x = 3 + square root of 3 or 3 - square root of 3