The perimeter of a rectangle is 30 ft, and the area of the rectangle is 56 ft^2.  What are the dimensions of the rectangle?
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1 Answer

rektangel...area=56=leng*wide

rim-leng=30, so half-rim=15=leng+wide

so leng=15-wide

leng*wide=(15-wide)*wide=56

-wide^2 +15wide -56=0

or wide^2 -15wide +56=0

wide=7 or 8...tri 7, then leng=8 & 7*8=56
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