Find the area of a regular pentagon

Find the area of a regular pentagon with side length = 12  (round your answer to the nearest whole number) is all i have help! I am stumped!
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rregular polygon, numsides=5, side leng=12

area=247.748746

inside angel=108 deg, outside angel=72deg

regular polygon area=(n/4)*side*side*tangent(beta)

n=number sides

draw lines from senter av polygon tu 2 ends av the bottom side

get isosaleez triangel & beta=its angel at the base

for n=5, beta=54 deg & tan(beta)=1.3763819205

get area av 1 such triangel, then multipli bi n
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