(3x^2)/9^x=27

Question

please, solve this problem

Answer 1

3x^2 / 9^x = 27

x^2 / 9^x = 9

x^2 = (9^x)(9^1)

x^2 = 9^(x + 1)

By observation and logic, the only possible answer is x = -1.

Answer 2

first multiply each side by 9^x

you get: 3x^2 = 27 x 9^x

now divide both sides by 3

you will get

x^2= 9 x 3^x

now you have to bring that x down so you have to take log base 3 of 3 to both sides

log 3 (x^2) =  log 3 (9) log 3 (3^x)

log 3 (x^2) = 2x

divide 2 on both sides

x = log base 3 (x^2) / 2

hope i did this right iam very tired its nearly 3 am

Comments

You did it wrong, the answer is -1.