log(3x+2)+log(x-1)=1

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1 Answer

log(3x+2) +log(x-2)=1

log[(3x+2)*(x-2)]=1

so (3x+2)*(x-2)=10, assume log base=10

3x^2+2x-6x-4-10=0

3x^2-4x-14=0

or (x-2.9274434)(x+1.59411)=0
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