1.) y=3x^2+1, 3.) y=x^2-18+12, 5.) y=3x^2+6x-8

find the equation of the axis of symmetry and the coordinates of the vertex of the graph of each function
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1 Answer

y=3x^2+1 is parabola, vertikal axis, ends go up

bottom at x=0 & y=1
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