4(0.3)^x = 1.2^(x+2)

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$4(0.3)^x = 1.2^{x+2} \\ \text{When you take logs,} \;ln(a^x) \; \text{can be written as} \; x ln(a) \text \;{therefore this becomes} \\ 4xln(0.3)= (x+2)ln(1.2) \\ \Rightarrow 4xln(0.3) = xln(1.2)+2ln(1.2) \\ \Rightarrow 4xln(0.3)- xln(1.2) = 2ln(1.2) \\ \Rightarrow x(4ln(0.3)-ln(1.2)) = 2ln(1.2) \\ \Rightarrow x = \frac{2ln(1.2)}{4ln(0.3)-ln(1.2)} = \frac{ln(1.2)}{2ln(0.3)}-2$

GeordieJake:)

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