I don't understand how to do problems like this

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$5x²+8x+3=0 \\ \text{The quadratic formula is a hideous looking equation, but is really nothing too scary.} \\ \text {The quad formula is} \; ; \frac{-b\pm \sqrt{b^2-4ac}}{2a} \\ \text {the} \; a \; \text{is the coefficient of} \; x^2, \; b \; \text{is the coefficient of} \; x \; \text{and c is the end number. In this} \\ \text{case,} \; a=5 \; , \; b=8 \; , \; c=3 \\ \text{now, all you do is plug the numbers into the formula.} \\ \frac{-8\pm \sqrt{8^2-4 \cdot 5 \cdot 3}}{2 \cdot 5} = \frac{-8 \pm \sqrt{64-60}}{10} = \frac{-8 \pm \sqrt4}{10} = \frac{-8 \pm 2}{10} \\ \text{There is either 2,1 or 0 solutions to these questions. As a solution is where the graph} \\ \text{crosses the x axis, if it goes below there will be 2 solutions, if it touches it there will} \\ \text{be 1 solution, and if it doesn't cross, there are no solutions. You will find out more} \\ \text{about this as you continue with maths. For the minute, there are 2 solutions, one at }$

$\\ \; \\ \text{the plus and one at the minus.} \\ \frac{-8+2}{10}= \frac{-6}{10} = \frac{-3}{5} \\ \; \\ \text {or} \\ \; \\ \frac{-8-2}{10}= \frac{-10}{10} = -1 \\ \; \\ \therefore x= \frac{-3}{5} \; or -1$

Geordie Jake :)

by Level 3 User (4.6k points)

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