how do you solve the cubic equation 1x^3-6x^2-7x=0?

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1 Answer

x^3 - 6x^2 - 7x = 0

 

Factor out the gcf, x, first then factor the remaining trinomial. Use zero product property to find the solutions.

x^3 - 6x^2 - 7x = 0  iff

x(x^2 - 6x - 7) = 0 iff

x(x - 7)(x + 1) = 0 iff

x = 0 or x - 7 = 0 or x + 1 = 0 iff

x = 0 or x = 7 or x = -1
by Level 1 User (660 points)

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