Find the area of a right triangle where th hypotenuse = 27' and one leg = 13

Question

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Answer 1

Find the area of a right triangle where th hypotenuse = 27' and one leg = 13

We need the length of the remaining side, which we will call h.

27^2 = 13^2 + h^2
729 = 169 + h^2
h^2 = 729 - 169
h^2 = 560
h = √560
h = 23.66

The area of a triangle is 1/2(bh). In this problem, b is 13.

A = 1/2 (bh)
A = 1/2 (13* 23.66)
A = 1/2 (307.58)

A = 153.79 sq ft